153340113 has 4 divisors (see below), whose sum is σ = 204453488. Its totient is φ = 102226740.

The previous prime is 153340097. The next prime is 153340133. The reversal of 153340113 is 311043351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311043351 = 3 ⋅103681117.

It is not a de Polignac number, because 153340113 - 2⁴ = 153340097 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 153340113.

It is not an unprimeable number, because it can be changed into a prime (153340133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25556683 + ... + 25556688.

It is an arithmetic number, because the mean of its divisors is an integer number (51113372).

Almost surely, 2^153340113 is an apocalyptic number.

It is an amenable number.

153340113 is a deficient number, since it is larger than the sum of its proper divisors (51113375).

153340113 is an equidigital number, since it uses as much as digits as its factorization.

153340113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51113374.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 153340113 is about 12383.0574980495. The cubic root of 153340113 is about 535.2441462900.

Adding to 153340113 its reverse (311043351), we get a palindrome (464383464).

The spelling of 153340113 in words is "one hundred fifty-three million, three hundred forty thousand, one hundred thirteen".