Base | Representation |
---|---|
bin | 1000111011001111011… |
… | …1001000110100001011 |
3 | 112122210121221210120011 |
4 | 2032303313020310023 |
5 | 10003020401243201 |
6 | 154235531012351 |
7 | 14035641441514 |
oct | 2166367106413 |
9 | 478717853504 |
10 | 153341431051 |
11 | 5a039270816 |
12 | 2587589a0b7 |
13 | 115c99097b3 |
14 | 75c9473a0b |
15 | 3ec7118151 |
hex | 23b3dc8d0b |
153341431051 has 4 divisors (see below), whose sum is σ = 153352814112. Its totient is φ = 153330047992.
The previous prime is 153341431031. The next prime is 153341431063. The reversal of 153341431051 is 150134143351.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 150134143351 = 10627 ⋅14127613.
It is a cyclic number.
It is not a de Polignac number, because 153341431051 - 215 = 153341398283 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (153341431031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5671300 + ... + 5698273.
It is an arithmetic number, because the mean of its divisors is an integer number (38338203528).
Almost surely, 2153341431051 is an apocalyptic number.
153341431051 is a deficient number, since it is larger than the sum of its proper divisors (11383061).
153341431051 is a wasteful number, since it uses less digits than its factorization.
153341431051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11383060.
The product of its (nonzero) digits is 10800, while the sum is 31.
The spelling of 153341431051 in words is "one hundred fifty-three billion, three hundred forty-one million, four hundred thirty-one thousand, fifty-one".
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