153402306000121 has 4 divisors (see below), whose sum is σ = 153405103886500. Its totient is φ = 153399508113744.

The previous prime is 153402306000113. The next prime is 153402306000143. The reversal of 153402306000121 is 121000603204351.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 53170872250896 + 100231433749225 = 7291836^2 + 10011565^2 .

It is a cyclic number.

It is not a de Polignac number, because 153402306000121 - 2³ = 153402306000113 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 153402306000121.

It is not an unprimeable number, because it can be changed into a prime (153402306000721) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1398860946 + ... + 1398970603.

It is an arithmetic number, because the mean of its divisors is an integer number (38351275971625).

Almost surely, 2^{153402306000121} is an apocalyptic number.

It is an amenable number.

153402306000121 is a deficient number, since it is larger than the sum of its proper divisors (2797886379).

153402306000121 is an equidigital number, since it uses as much as digits as its factorization.

153402306000121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2797886378.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 153402306000121 its reverse (121000603204351), we get a palindrome (274402909204472).

The spelling of 153402306000121 in words is "one hundred fifty-three trillion, four hundred two billion, three hundred six million, one hundred twenty-one", and thus it is an aban number.