Base | Representation |
---|---|
bin | 11100100100101101… |
… | …10001000000110001 |
3 | 1110121002120011222122 |
4 | 32102112301000301 |
5 | 222404111441340 |
6 | 11014112444025 |
7 | 1052101524035 |
oct | 162226610061 |
9 | 43532504878 |
10 | 15340343345 |
11 | 6562251008 |
12 | 2b81549615 |
13 | 15a6200a52 |
14 | a574da1c5 |
15 | 5ebb41db5 |
hex | 3925b1031 |
15340343345 has 4 divisors (see below), whose sum is σ = 18408412020. Its totient is φ = 12272274672.
The previous prime is 15340343309. The next prime is 15340343399. The reversal of 15340343345 is 54334304351.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 6759470656 + 8580872689 = 82216^2 + 92633^2 .
It is a cyclic number.
It is not a de Polignac number, because 15340343345 - 230 = 14266601521 is a prime.
It is a super-2 number, since 2×153403433452 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1534034330 + ... + 1534034339.
It is an arithmetic number, because the mean of its divisors is an integer number (4602103005).
Almost surely, 215340343345 is an apocalyptic number.
It is an amenable number.
15340343345 is a deficient number, since it is larger than the sum of its proper divisors (3068068675).
15340343345 is an equidigital number, since it uses as much as digits as its factorization.
15340343345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3068068674.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 15340343345 its reverse (54334304351), we get a palindrome (69674647696).
The spelling of 15340343345 in words is "fifteen billion, three hundred forty million, three hundred forty-three thousand, three hundred forty-five".
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