1535001300401 has 4 divisors (see below), whose sum is σ = 1539277070400. Its totient is φ = 1530725530404.

The previous prime is 1535001300389. The next prime is 1535001300403. The reversal of 1535001300401 is 1040031005351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1535001300401 - 2³⁰ = 1533927558577 is a prime.

It is a super-2 number, since 2×1535001300401² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1535001300403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2137884461 + ... + 2137885178.

It is an arithmetic number, because the mean of its divisors is an integer number (384819267600).

Almost surely, 2^{1535001300401} is an apocalyptic number.

It is an amenable number.

1535001300401 is a deficient number, since it is larger than the sum of its proper divisors (4275769999).

1535001300401 is an equidigital number, since it uses as much as digits as its factorization.

1535001300401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4275769998.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 1535001300401 its reverse (1040031005351), we get a palindrome (2575032305752).

The spelling of 1535001300401 in words is "one trillion, five hundred thirty-five billion, one million, three hundred thousand, four hundred one".