Base | Representation |
---|---|
bin | 101101111001100… |
… | …1001010011101001 |
3 | 10222100000220211111 |
4 | 1123303021103221 |
5 | 11123233242441 |
6 | 412454230321 |
7 | 53110631641 |
oct | 13363112351 |
9 | 3870026744 |
10 | 1540134121 |
11 | 720402619 |
12 | 36b9553a1 |
13 | 1b7104b86 |
14 | 10878d521 |
15 | 90326081 |
hex | 5bcc94e9 |
1540134121 has 4 divisors (see below), whose sum is σ = 1541514052. Its totient is φ = 1538754192.
The previous prime is 1540134109. The next prime is 1540134133. The reversal of 1540134121 is 1214310451.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1214310451 = 1013 ⋅1198727.
It is an interprime number because it is at equal distance from previous prime (1540134109) and next prime (1540134133).
It can be written as a sum of positive squares in 2 ways, for example, as 720170896 + 819963225 = 26836^2 + 28635^2 .
It is a cyclic number.
It is not a de Polignac number, because 1540134121 - 211 = 1540132073 is a prime.
It is a super-2 number, since 2×15401341212 = 4744026221336885282, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1540134092 and 1540134101.
It is not an unprimeable number, because it can be changed into a prime (1540134181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 688290 + ... + 690523.
It is an arithmetic number, because the mean of its divisors is an integer number (385378513).
Almost surely, 21540134121 is an apocalyptic number.
It is an amenable number.
1540134121 is a deficient number, since it is larger than the sum of its proper divisors (1379931).
1540134121 is a wasteful number, since it uses less digits than its factorization.
1540134121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1379930.
The product of its (nonzero) digits is 480, while the sum is 22.
The square root of 1540134121 is about 39244.5425632660. The cubic root of 1540134121 is about 1154.8338737724.
Adding to 1540134121 its reverse (1214310451), we get a palindrome (2754444572).
The spelling of 1540134121 in words is "one billion, five hundred forty million, one hundred thirty-four thousand, one hundred twenty-one".
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