15401421249 has 4 divisors (see below), whose sum is σ = 20535228336. Its totient is φ = 10267614164.

The previous prime is 15401421247. The next prime is 15401421251. The reversal of 15401421249 is 94212410451.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 94212410451 = 3 ⋅31404136817.

It is an interprime number because it is at equal distance from previous prime (15401421247) and next prime (15401421251).

It is a cyclic number.

It is not a de Polignac number, because 15401421249 - 2¹ = 15401421247 is a prime.

It is not an unprimeable number, because it can be changed into a prime (15401421247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2566903539 + ... + 2566903544.

It is an arithmetic number, because the mean of its divisors is an integer number (5133807084).

Almost surely, 2^15401421249 is an apocalyptic number.

It is an amenable number.

15401421249 is a deficient number, since it is larger than the sum of its proper divisors (5133807087).

15401421249 is an equidigital number, since it uses as much as digits as its factorization.

15401421249 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5133807086.

The product of its (nonzero) digits is 11520, while the sum is 33.

The spelling of 15401421249 in words is "fifteen billion, four hundred one million, four hundred twenty-one thousand, two hundred forty-nine".