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154045442121 = 351348480707
BaseRepresentation
bin1000111101110111010…
…0101110100001001001
3112201121200200021012020
42033131310232201021
510010441113121441
6154433440235053
714062250440104
oct2173564564111
9481550607166
10154045442121
115a36a6aa74a
1225a3160ba89
13116ac7217ac
147654b7373b
154018d2de66
hex23ddd2e849

154045442121 has 4 divisors (see below), whose sum is σ = 205393922832. Its totient is φ = 102696961412.

The previous prime is 154045442069. The next prime is 154045442147. The reversal of 154045442121 is 121244540451.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121244540451 = 340414846817.

It is a cyclic number.

It is not a de Polignac number, because 154045442121 - 27 = 154045441993 is a prime.

It is not an unprimeable number, because it can be changed into a prime (154045442191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25674240351 + ... + 25674240356.

It is an arithmetic number, because the mean of its divisors is an integer number (51348480708).

Almost surely, 2154045442121 is an apocalyptic number.

It is an amenable number.

154045442121 is a deficient number, since it is larger than the sum of its proper divisors (51348480711).

154045442121 is an equidigital number, since it uses as much as digits as its factorization.

154045442121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51348480710.

The product of its (nonzero) digits is 25600, while the sum is 33.

Adding to 154045442121 its reverse (121244540451), we get a palindrome (275289982572).

The spelling of 154045442121 in words is "one hundred fifty-four billion, forty-five million, four hundred forty-two thousand, one hundred twenty-one".

Divisors: 1 3 51348480707 154045442121