Search a number
-
+
15412665131419 = 65492323533553
BaseRepresentation
bin1110000001001000101001…
…1011100010000110011011
32000120102210010121002100211
43200102022123202012123
54010010114233201134
652440251451311551
73150346132012033
oct340221233420633
960512703532324
1015412665131419
114a02524728636
12188b0b244b5b7
1387a53c743a0a
143b3d96b548c3
151badbadb4764
hexe048a6e219b

15412665131419 has 4 divisors (see below), whose sum is σ = 15412689319896. Its totient is φ = 15412640942944.

The previous prime is 15412665131401. The next prime is 15412665131449. The reversal of 15412665131419 is 91413156621451.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15412665131419 is a prime.

It is a super-2 number, since 2×154126651314192 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15412665131449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11111854 + ... + 12421699.

It is an arithmetic number, because the mean of its divisors is an integer number (3853172329974).

Almost surely, 215412665131419 is an apocalyptic number.

15412665131419 is a deficient number, since it is larger than the sum of its proper divisors (24188477).

15412665131419 is an equidigital number, since it uses as much as digits as its factorization.

15412665131419 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24188476.

The product of its digits is 777600, while the sum is 49.

The spelling of 15412665131419 in words is "fifteen trillion, four hundred twelve billion, six hundred sixty-five million, one hundred thirty-one thousand, four hundred nineteen".

Divisors: 1 654923 23533553 15412665131419