15440134033 has 4 divisors (see below), whose sum is σ = 15701831280. Its totient is φ = 15178436788.

The previous prime is 15440134019. The next prime is 15440134063. The reversal of 15440134033 is 33043104451.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33043104451 = 7 ⋅4720443493.

It is a cyclic number.

It is not a de Polignac number, because 15440134033 - 2⁹ = 15440133521 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15440133992 and 15440134010.

It is not an unprimeable number, because it can be changed into a prime (15440134063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130848535 + ... + 130848652.

It is an arithmetic number, because the mean of its divisors is an integer number (3925457820).

Almost surely, 2^15440134033 is an apocalyptic number.

It is an amenable number.

15440134033 is a deficient number, since it is larger than the sum of its proper divisors (261697247).

15440134033 is an equidigital number, since it uses as much as digits as its factorization.

15440134033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 261697246.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 15440134033 its reverse (33043104451), we get a palindrome (48483238484).

The spelling of 15440134033 in words is "fifteen billion, four hundred forty million, one hundred thirty-four thousand, thirty-three".