Base | Representation |
---|---|
bin | 1110000010110111100101… |
… | …1001011001011110011001 |
3 | 2000200021122111000222001122 |
4 | 3200231321121121132121 |
5 | 4011002111144131301 |
6 | 52502054430455025 |
7 | 3152452106224334 |
oct | 340557131313631 |
9 | 60607574028048 |
10 | 15442444130201 |
11 | 4a14116145130 |
12 | 1894a23364475 |
13 | 8802a70aa75a |
14 | 3b55bdab161b |
15 | 1bba603d681b |
hex | e0b79659799 |
15442444130201 has 16 divisors (see below), whose sum is σ = 17771753261760. Its totient is φ = 13270610350080.
The previous prime is 15442444130161. The next prime is 15442444130207. The reversal of 15442444130201 is 10203144424451.
It is a de Polignac number, because none of the positive numbers 2k-15442444130201 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (15442444130207) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80743976 + ... + 80935001.
It is an arithmetic number, because the mean of its divisors is an integer number (1110734578860).
Almost surely, 215442444130201 is an apocalyptic number.
15442444130201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
15442444130201 is a deficient number, since it is larger than the sum of its proper divisors (2329309131559).
15442444130201 is a wasteful number, since it uses less digits than its factorization.
15442444130201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161679464.
The product of its (nonzero) digits is 61440, while the sum is 35.
Adding to 15442444130201 its reverse (10203144424451), we get a palindrome (25645588554652).
The spelling of 15442444130201 in words is "fifteen trillion, four hundred forty-two billion, four hundred forty-four million, one hundred thirty thousand, two hundred one".
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