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155030113 = 722147159
BaseRepresentation
bin10010011110110…
…01001001100001
3101210201100100001
421033121021201
5304141430423
623214500001
73561506560
oct1117311141
9353640301
10155030113
117a568467
1243b04601
13261705c4
1416837bd7
15d924cad
hex93d9261

155030113 has 4 divisors (see below), whose sum is σ = 177177280. Its totient is φ = 132882948.

The previous prime is 155030107. The next prime is 155030129. The reversal of 155030113 is 311030551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 155030113 - 29 = 155029601 is a prime.

It is not an unprimeable number, because it can be changed into a prime (155030713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11073573 + ... + 11073586.

It is an arithmetic number, because the mean of its divisors is an integer number (44294320).

Almost surely, 2155030113 is an apocalyptic number.

It is an amenable number.

155030113 is a deficient number, since it is larger than the sum of its proper divisors (22147167).

155030113 is an equidigital number, since it uses as much as digits as its factorization.

155030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22147166.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 155030113 is about 12451.1089064388. The cubic root of 155030113 is about 537.2033198143.

Adding to 155030113 its reverse (311030551), we get a palindrome (466060664).

The spelling of 155030113 in words is "one hundred fifty-five million, thirty thousand, one hundred thirteen".

Divisors: 1 7 22147159 155030113