Base | Representation |
---|---|
bin | 10110100011111011110… |
… | …000111110000111011001 |
3 | 12111012212212222110011020 |
4 | 112203323300332013121 |
5 | 200400221002120423 |
6 | 3144125520553053 |
7 | 220004441535366 |
oct | 26437360760731 |
9 | 5435785873136 |
10 | 1550412145113 |
11 | 548587267137 |
12 | 210591a82789 |
13 | b328468a980 |
14 | 5507ca0346d |
15 | 2a4e30014e3 |
hex | 168fbc3e1d9 |
1550412145113 has 16 divisors (see below), whose sum is σ = 2286401280576. Its totient is φ = 928313300160.
The previous prime is 1550412145099. The next prime is 1550412145151. The reversal of 1550412145113 is 3115412140551.
It is not a de Polignac number, because 1550412145113 - 25 = 1550412145081 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1550412145153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 537216903 + ... + 537219788.
It is an arithmetic number, because the mean of its divisors is an integer number (142900080036).
Almost surely, 21550412145113 is an apocalyptic number.
1550412145113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1550412145113 is a deficient number, since it is larger than the sum of its proper divisors (735989135463).
1550412145113 is a wasteful number, since it uses less digits than its factorization.
1550412145113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1074436744.
The product of its (nonzero) digits is 12000, while the sum is 33.
Adding to 1550412145113 its reverse (3115412140551), we get a palindrome (4665824285664).
The spelling of 1550412145113 in words is "one trillion, five hundred fifty billion, four hundred twelve million, one hundred forty-five thousand, one hundred thirteen".
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