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155105113 = 198163427
BaseRepresentation
bin10010011111010…
…11011101011001
3101210212011012211
421033223131121
5304201330423
623220235121
73562241332
oct1117533531
9353764184
10155105113
117a609849
1243b3baa1
1326198797
1416857289
15d93c10d
hex93eb759

155105113 has 4 divisors (see below), whose sum is σ = 163268560. Its totient is φ = 146941668.

The previous prime is 155105099. The next prime is 155105129. The reversal of 155105113 is 311501551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 155105113 - 25 = 155105081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (155105213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4081695 + ... + 4081732.

It is an arithmetic number, because the mean of its divisors is an integer number (40817140).

Almost surely, 2155105113 is an apocalyptic number.

It is an amenable number.

155105113 is a deficient number, since it is larger than the sum of its proper divisors (8163447).

155105113 is an equidigital number, since it uses as much as digits as its factorization.

155105113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8163446.

The product of its (nonzero) digits is 375, while the sum is 22.

The square root of 155105113 is about 12454.1203222066. The cubic root of 155105113 is about 537.2899347150.

Adding to 155105113 its reverse (311501551), we get a palindrome (466606664).

The spelling of 155105113 in words is "one hundred fifty-five million, one hundred five thousand, one hundred thirteen".

Divisors: 1 19 8163427 155105113