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155122041 = 351707347
BaseRepresentation
bin10010011111011…
…11100101111001
3101210220000102210
421033233211321
5304202401131
623220445333
73562341564
oct1117574571
9353800383
10155122041
117a620538
1243b49849
13261a33b9
141685d4db
15d942146
hex93ef979

155122041 has 4 divisors (see below), whose sum is σ = 206829392. Its totient is φ = 103414692.

The previous prime is 155122021. The next prime is 155122063. The reversal of 155122041 is 140221551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 155122041 - 26 = 155121977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 155121999 and 155122017.

It is not an unprimeable number, because it can be changed into a prime (155122001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25853671 + ... + 25853676.

It is an arithmetic number, because the mean of its divisors is an integer number (51707348).

Almost surely, 2155122041 is an apocalyptic number.

It is an amenable number.

155122041 is a deficient number, since it is larger than the sum of its proper divisors (51707351).

155122041 is an equidigital number, since it uses as much as digits as its factorization.

155122041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51707350.

The product of its (nonzero) digits is 400, while the sum is 21.

The square root of 155122041 is about 12454.7999181039. The cubic root of 155122041 is about 537.3094804132.

Adding to 155122041 its reverse (140221551), we get a palindrome (295343592).

The spelling of 155122041 in words is "one hundred fifty-five million, one hundred twenty-two thousand, forty-one".

Divisors: 1 3 51707347 155122041