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1551421234131 = 32273922742443
BaseRepresentation
bin10110100100110111111…
…010010101101111010011
312111022111012202111001120
4112210313322111233103
5200404302313443011
63144414005133323
7220041443623026
oct26446772255723
95438435674046
101551421234131
11548a549286aa
122108139ba243
13b33b575ab72
1455136a391bd
152a5518caa06
hex16937e95bd3

1551421234131 has 8 divisors (see below), whose sum is σ = 2068652706240. Its totient is φ = 1034235292392.

The previous prime is 1551421234117. The next prime is 1551421234133. The reversal of 1551421234131 is 1314321241551.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1551421234131 - 29 = 1551421233619 is a prime.

It is a super-2 number, since 2×15514212341312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1551421234092 and 1551421234101.

It is not an unprimeable number, because it can be changed into a prime (1551421234133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11303005 + ... + 11439438.

It is an arithmetic number, because the mean of its divisors is an integer number (258581588280).

Almost surely, 21551421234131 is an apocalyptic number.

1551421234131 is a deficient number, since it is larger than the sum of its proper divisors (517231472109).

1551421234131 is a wasteful number, since it uses less digits than its factorization.

1551421234131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22765185.

The product of its digits is 14400, while the sum is 33.

Adding to 1551421234131 its reverse (1314321241551), we get a palindrome (2865742475682).

The spelling of 1551421234131 in words is "one trillion, five hundred fifty-one billion, four hundred twenty-one million, two hundred thirty-four thousand, one hundred thirty-one".

Divisors: 1 3 22739 68217 22742443 68227329 517140411377 1551421234131