Base | Representation |
---|---|
bin | 100011010011000101010100… |
… | …100101111001100111101011 |
3 | 202100200002100102210110211010 |
4 | 203103011110211321213223 |
5 | 130322000142101313103 |
6 | 1310101353310035003 |
7 | 44461636363451313 |
oct | 4323052445714753 |
9 | 670602312713733 |
10 | 155243012135403 |
11 | 4551321219a965 |
12 | 154b31767a8a63 |
13 | 688147907492a |
14 | 2a49b324d6443 |
15 | 12e336124b903 |
hex | 8d31549799eb |
155243012135403 has 8 divisors (see below), whose sum is σ = 206994476674368. Its totient is φ = 103493444510024.
The previous prime is 155243012135399. The next prime is 155243012135429. The reversal of 155243012135403 is 304531210342551.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 155243012135403 - 22 = 155243012135399 is a prime.
It is not an unprimeable number, because it can be changed into a prime (155243012135483) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 474037425 + ... + 474364802.
It is an arithmetic number, because the mean of its divisors is an integer number (25874309584296).
Almost surely, 2155243012135403 is an apocalyptic number.
155243012135403 is a deficient number, since it is larger than the sum of its proper divisors (51751464538965).
155243012135403 is an equidigital number, since it uses as much as digits as its factorization.
155243012135403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 948456793.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 155243012135403 its reverse (304531210342551), we get a palindrome (459774222477954).
The spelling of 155243012135403 in words is "one hundred fifty-five trillion, two hundred forty-three billion, twelve million, one hundred thirty-five thousand, four hundred three".
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