Search a number
-
+
15530112131 = 84671834193
BaseRepresentation
bin11100111011010101…
…01011010010000011
31111002022122102211012
432131222223102003
5223301202042011
611045012111135
71056564526562
oct163552532203
944068572735
1015530112131
11664a386116
1230150054ab
131606615181
14a747b7bd9
1560d629a8b
hex39daab483

15530112131 has 4 divisors (see below), whose sum is σ = 15531954792. Its totient is φ = 15528269472.

The previous prime is 15530112113. The next prime is 15530112139. The reversal of 15530112131 is 13121103551.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15530112131 is a prime.

It is a super-2 number, since 2×155301121312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15530112097 and 15530112106.

It is not an unprimeable number, because it can be changed into a prime (15530112139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 908630 + ... + 925563.

It is an arithmetic number, because the mean of its divisors is an integer number (3882988698).

Almost surely, 215530112131 is an apocalyptic number.

15530112131 is a deficient number, since it is larger than the sum of its proper divisors (1842661).

15530112131 is an equidigital number, since it uses as much as digits as its factorization.

15530112131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1842660.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 15530112131 its reverse (13121103551), we get a palindrome (28651215682).

The spelling of 15530112131 in words is "fifteen billion, five hundred thirty million, one hundred twelve thousand, one hundred thirty-one".

Divisors: 1 8467 1834193 15530112131