Base | Representation |
---|---|
bin | 10110100110011110000… |
… | …001010100111110010011 |
3 | 12111110220121021101022110 |
4 | 112212132001110332103 |
5 | 200421304342421120 |
6 | 3145300003040403 |
7 | 220132055040513 |
oct | 26463601247623 |
9 | 5443817241273 |
10 | 1553134342035 |
11 | 549753933a61 |
12 | 211011670103 |
13 | b35c9646793 |
14 | 5525a373843 |
15 | 2a601ebd2e0 |
hex | 1699e054f93 |
1553134342035 has 16 divisors (see below), whose sum is σ = 2486887635456. Its totient is φ = 827714086368.
The previous prime is 1553134342031. The next prime is 1553134342063. The reversal of 1553134342035 is 5302434313551.
It is not a de Polignac number, because 1553134342035 - 22 = 1553134342031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1553134341984 and 1553134342002.
It is not an unprimeable number, because it can be changed into a prime (1553134342031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38993769 + ... + 39033578.
It is an arithmetic number, because the mean of its divisors is an integer number (155430477216).
Almost surely, 21553134342035 is an apocalyptic number.
1553134342035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1553134342035 is a deficient number, since it is larger than the sum of its proper divisors (933753293421).
1553134342035 is a wasteful number, since it uses less digits than its factorization.
1553134342035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 78028682.
The product of its (nonzero) digits is 324000, while the sum is 39.
Adding to 1553134342035 its reverse (5302434313551), we get a palindrome (6855568655586).
The spelling of 1553134342035 in words is "one trillion, five hundred fifty-three billion, one hundred thirty-four million, three hundred forty-two thousand, thirty-five".
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