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15540331441 = 113137525057
BaseRepresentation
bin11100111100100011…
…01010001110110001
31111010000212122002011
432132101222032301
5223311311101231
611050015122521
71060050431515
oct163621521661
944100778064
1015540331441
116655126028
123018513441
1316087827bb
14a75cb8145
1560e4979b1
hex39e46a3b1

15540331441 has 4 divisors (see below), whose sum is σ = 15677856612. Its totient is φ = 15402806272.

The previous prime is 15540331379. The next prime is 15540331487. The reversal of 15540331441 is 14413304551.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8226490000 + 7313841441 = 90700^2 + 85521^2 .

It is a cyclic number.

It is not a de Polignac number, because 15540331441 - 217 = 15540200369 is a prime.

It is a super-2 number, since 2×155403314412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15540331141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68762416 + ... + 68762641.

It is an arithmetic number, because the mean of its divisors is an integer number (3919464153).

Almost surely, 215540331441 is an apocalyptic number.

It is an amenable number.

15540331441 is a deficient number, since it is larger than the sum of its proper divisors (137525171).

15540331441 is a wasteful number, since it uses less digits than its factorization.

15540331441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137525170.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 15540331441 its reverse (14413304551), we get a palindrome (29953635992).

The spelling of 15540331441 in words is "fifteen billion, five hundred forty million, three hundred thirty-one thousand, four hundred forty-one".

Divisors: 1 113 137525057 15540331441