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1554439431913 = 4271363952103
BaseRepresentation
bin10110100111101011110…
…011110110011011101001
312111121021120000211001121
4112213223303312123221
5200431442443310123
63150033303415241
7220206313110334
oct26475363663351
95447246024047
101554439431913
1154a263598335
12211316754521
13b3776b44404
145534181b61b
152a67b86675d
hex169ebcf66e9

1554439431913 has 4 divisors (see below), whose sum is σ = 1554803388288. Its totient is φ = 1554075475540.

The previous prime is 1554439431907. The next prime is 1554439431949. The reversal of 1554439431913 is 3191349344551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1554439431913 - 237 = 1417000478441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1554439431313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 181971781 + ... + 181980322.

It is an arithmetic number, because the mean of its divisors is an integer number (388700847072).

Almost surely, 21554439431913 is an apocalyptic number.

It is an amenable number.

1554439431913 is a deficient number, since it is larger than the sum of its proper divisors (363956375).

1554439431913 is an equidigital number, since it uses as much as digits as its factorization.

1554439431913 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 363956374.

The product of its digits is 3499200, while the sum is 52.

The spelling of 1554439431913 in words is "one trillion, five hundred fifty-four billion, four hundred thirty-nine million, four hundred thirty-one thousand, nine hundred thirteen".

Divisors: 1 4271 363952103 1554439431913