Base | Representation |
---|---|
bin | 1001000011010010110… |
… | …1110010011110011001 |
3 | 112212101021210010110111 |
4 | 2100310231302132121 |
5 | 10021432312203423 |
6 | 155234234044321 |
7 | 14143341511663 |
oct | 2206455623631 |
9 | 485337703414 |
10 | 155503241113 |
11 | 5aa48586700 |
12 | 261798796a1 |
13 | 1188275944c |
14 | 775260d533 |
15 | 40a1cde60d |
hex | 2434b72799 |
155503241113 has 12 divisors (see below), whose sum is σ = 170947687680. Its totient is φ = 141347860280.
The previous prime is 155503241093. The next prime is 155503241119. The reversal of 155503241113 is 311142305551.
155503241113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 155503241113 - 217 = 155503110041 is a prime.
It is not an unprimeable number, because it can be changed into a prime (155503241119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 877056 + ... + 1039342.
It is an arithmetic number, because the mean of its divisors is an integer number (14245640640).
Almost surely, 2155503241113 is an apocalyptic number.
It is an amenable number.
155503241113 is a deficient number, since it is larger than the sum of its proper divisors (15444446567).
155503241113 is a wasteful number, since it uses less digits than its factorization.
155503241113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 170228 (or 170217 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 155503241113 its reverse (311142305551), we get a palindrome (466645546664).
The spelling of 155503241113 in words is "one hundred fifty-five billion, five hundred three million, two hundred forty-one thousand, one hundred thirteen".
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