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155503241113 = 1127919162287
BaseRepresentation
bin1001000011010010110…
…1110010011110011001
3112212101021210010110111
42100310231302132121
510021432312203423
6155234234044321
714143341511663
oct2206455623631
9485337703414
10155503241113
115aa48586700
12261798796a1
131188275944c
14775260d533
1540a1cde60d
hex2434b72799

155503241113 has 12 divisors (see below), whose sum is σ = 170947687680. Its totient is φ = 141347860280.

The previous prime is 155503241093. The next prime is 155503241119. The reversal of 155503241113 is 311142305551.

155503241113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 155503241113 - 217 = 155503110041 is a prime.

It is not an unprimeable number, because it can be changed into a prime (155503241119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 877056 + ... + 1039342.

It is an arithmetic number, because the mean of its divisors is an integer number (14245640640).

Almost surely, 2155503241113 is an apocalyptic number.

It is an amenable number.

155503241113 is a deficient number, since it is larger than the sum of its proper divisors (15444446567).

155503241113 is a wasteful number, since it uses less digits than its factorization.

155503241113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170228 (or 170217 counting only the distinct ones).

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 155503241113 its reverse (311142305551), we get a palindrome (466645546664).

The spelling of 155503241113 in words is "one hundred fifty-five billion, five hundred three million, two hundred forty-one thousand, one hundred thirteen".

Divisors: 1 11 121 7919 87109 162287 958199 1785157 19636727 1285150753 14136658283 155503241113