Base | Representation |
---|---|
bin | 10110101000100101001… |
… | …001001011101111011011 |
3 | 12111200202121000002001011 |
4 | 112220211021023233123 |
5 | 200440430214404111 |
6 | 3150312544234351 |
7 | 220242203061034 |
oct | 26504511135733 |
9 | 5450677002034 |
10 | 1555401325531 |
11 | 54a707554239 |
12 | 21154490b9b7 |
13 | b389b1cb931 |
14 | 553d3489a8b |
15 | 2a6d601c021 |
hex | 16a2524bbdb |
1555401325531 has 4 divisors (see below), whose sum is σ = 1597439199232. Its totient is φ = 1513363451832.
The previous prime is 1555401325477. The next prime is 1555401325571. The reversal of 1555401325531 is 1355231045551.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1555401325531 - 231 = 1553253841883 is a prime.
It is a super-2 number, since 2×15554013255312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1555401325571) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21018936795 + ... + 21018936868.
It is an arithmetic number, because the mean of its divisors is an integer number (399359799808).
Almost surely, 21555401325531 is an apocalyptic number.
1555401325531 is a deficient number, since it is larger than the sum of its proper divisors (42037873701).
1555401325531 is an equidigital number, since it uses as much as digits as its factorization.
1555401325531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42037873700.
The product of its (nonzero) digits is 225000, while the sum is 40.
The spelling of 1555401325531 in words is "one trillion, five hundred fifty-five billion, four hundred one million, three hundred twenty-five thousand, five hundred thirty-one".
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