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155544305113 = 200461775933
BaseRepresentation
bin1001000011011100101…
…0011011110111011001
3112212111011001101200101
42100313022123313121
510022023320230423
6155242302135401
714144350531051
oct2206712336731
9485434041611
10155544305113
115aa6978369a
122618b581561
131188b106382
147757c5c561
1540a57017ad
hex243729bdd9

155544305113 has 4 divisors (see below), whose sum is σ = 155545281508. Its totient is φ = 155543328720.

The previous prime is 155544305107. The next prime is 155544305117. The reversal of 155544305113 is 311503445551.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 311503445551 = 734267170487.

It can be written as a sum of positive squares in 2 ways, for example, as 94612838464 + 60931466649 = 307592^2 + 246843^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-155544305113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (155544305117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 187506 + ... + 588427.

It is an arithmetic number, because the mean of its divisors is an integer number (38886320377).

Almost surely, 2155544305113 is an apocalyptic number.

It is an amenable number.

155544305113 is a deficient number, since it is larger than the sum of its proper divisors (976395).

155544305113 is an equidigital number, since it uses as much as digits as its factorization.

155544305113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 976394.

The product of its (nonzero) digits is 90000, while the sum is 37.

The spelling of 155544305113 in words is "one hundred fifty-five billion, five hundred forty-four million, three hundred five thousand, one hundred thirteen".

Divisors: 1 200461 775933 155544305113