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1555500000001 = 4691331592411
BaseRepresentation
bin10110101000101011000…
…001100110001100000001
312111201000110200020222011
4112220223001212030001
5200441131000000001
63150330431212521
7220244511562513
oct26505301461401
95451013606864
101555500000001
1154a75821a892
12211571977141
13b38b5799cac
1455402613bb3
152a6dea0dd51
hex16a2b066301

1555500000001 has 4 divisors (see below), whose sum is σ = 1555831597104. Its totient is φ = 1555168402900.

The previous prime is 1555499999923. The next prime is 1555500000023. The reversal of 1555500000001 is 1000000055551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1555500000001 - 27 = 1555499999873 is a prime.

It is a super-2 number, since 2×15555000000012 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1555500000071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 165791515 + ... + 165800896.

It is an arithmetic number, because the mean of its divisors is an integer number (388957899276).

Almost surely, 21555500000001 is an apocalyptic number.

It is an amenable number.

1555500000001 is a deficient number, since it is larger than the sum of its proper divisors (331597103).

1555500000001 is an equidigital number, since it uses as much as digits as its factorization.

1555500000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 331597102.

The product of its (nonzero) digits is 625, while the sum is 22.

Adding to 1555500000001 its reverse (1000000055551), we get a palindrome (2555500055552).

The spelling of 1555500000001 in words is "one trillion, five hundred fifty-five billion, five hundred million, one", and thus it is an aban number.

Divisors: 1 4691 331592411 1555500000001