15600113 has 4 divisors (see below), whose sum is σ = 15617700. Its totient is φ = 15582528.

The previous prime is 15600097. The next prime is 15600119. The reversal of 15600113 is 31100651.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31100651 = 113 ⋅275227.

It can be written as a sum of positive squares in 2 ways, for example, as 5721664 + 9878449 = 2392^2 + 3143^2 .

It is a cyclic number.

It is not a de Polignac number, because 15600113 - 2⁴ = 15600097 is a prime.

It is a super-2 number, since 2×15600113² = 486727051225538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 15600091 and 15600100.

It is not an unprimeable number, because it can be changed into a prime (15600119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7388 + ... + 9261.

It is an arithmetic number, because the mean of its divisors is an integer number (3904425).

Almost surely, 2^15600113 is an apocalyptic number.

It is an amenable number.

15600113 is a deficient number, since it is larger than the sum of its proper divisors (17587).

15600113 is an equidigital number, since it uses as much as digits as its factorization.

15600113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17586.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 15600113 is about 3949.6978365440. The cubic root of 15600113 is about 249.8671988012.

Adding to 15600113 its reverse (31100651), we get a palindrome (46700764).

The spelling of 15600113 in words is "fifteen million, six hundred thousand, one hundred thirteen".