Base | Representation |
---|---|
bin | 1110010000101111110111… |
… | …0110110001101011111011 |
3 | 2001112002010011022011021101 |
4 | 3210023331312301223323 |
5 | 4023403430221002324 |
6 | 53203411245152231 |
7 | 3205623030415111 |
oct | 344137566615373 |
9 | 61462104264241 |
10 | 15680889625339 |
11 | 4aa6256436904 |
12 | 191308a25b677 |
13 | 8999173b5203 |
14 | 3c2d5db0dab1 |
15 | 1c2d68b2d944 |
hex | e42fddb1afb |
15680889625339 has 4 divisors (see below), whose sum is σ = 16506199605640. Its totient is φ = 14855579645040.
The previous prime is 15680889625333. The next prime is 15680889625363. The reversal of 15680889625339 is 93352698808651.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 15680889625339 - 211 = 15680889623291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15680889625333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 412654990122 + ... + 412654990159.
It is an arithmetic number, because the mean of its divisors is an integer number (4126549901410).
Almost surely, 215680889625339 is an apocalyptic number.
15680889625339 is a gapful number since it is divisible by the number (19) formed by its first and last digit.
15680889625339 is a deficient number, since it is larger than the sum of its proper divisors (825309980301).
15680889625339 is an equidigital number, since it uses as much as digits as its factorization.
15680889625339 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 825309980300.
The product of its (nonzero) digits is 671846400, while the sum is 73.
The spelling of 15680889625339 in words is "fifteen trillion, six hundred eighty billion, eight hundred eighty-nine million, six hundred twenty-five thousand, three hundred thirty-nine".
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