160113400344211 has 4 divisors (see below), whose sum is σ = 160380701514000. Its totient is φ = 159846099174424.

The previous prime is 160113400344173. The next prime is 160113400344343. The reversal of 160113400344211 is 112443004311061.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 160113400344211 - 2¹⁵ = 160113400311443 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (160113400144211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133650583996 + ... + 133650585193.

It is an arithmetic number, because the mean of its divisors is an integer number (40095175378500).

Almost surely, 2^{160113400344211} is an apocalyptic number.

160113400344211 is a deficient number, since it is larger than the sum of its proper divisors (267301169789).

160113400344211 is an equidigital number, since it uses as much as digits as its factorization.

160113400344211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 267301169788.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 160113400344211 its reverse (112443004311061), we get a palindrome (272556404655272).

The spelling of 160113400344211 in words is "one hundred sixty trillion, one hundred thirteen billion, four hundred million, three hundred forty-four thousand, two hundred eleven".