160492043900913 has 4 divisors (see below), whose sum is σ = 213989391867888. Its totient is φ = 106994695933940.

The previous prime is 160492043900861. The next prime is 160492043900917. The reversal of 160492043900913 is 319009340294061.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 160492043900913 - 2⁹ = 160492043900401 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (160492043900917) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26748673983483 + ... + 26748673983488.

It is an arithmetic number, because the mean of its divisors is an integer number (53497347966972).

Almost surely, 2^{160492043900913} is an apocalyptic number.

It is an amenable number.

160492043900913 is a deficient number, since it is larger than the sum of its proper divisors (53497347966975).

160492043900913 is an equidigital number, since it uses as much as digits as its factorization.

160492043900913 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 53497347966974.

The product of its (nonzero) digits is 1259712, while the sum is 51.

The spelling of 160492043900913 in words is "one hundred sixty trillion, four hundred ninety-two billion, forty-three million, nine hundred thousand, nine hundred thirteen".