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16053300035 = 53210660007
BaseRepresentation
bin11101111001101100…
…11110101101000011
31112102210010010200222
432330312132231003
5230334121100120
611212541533255
71105546541003
oct167466365503
945383103628
1016053300035
11689873aa13
12314027422b
13168ab28706
14ac4088003
1563e523525
hex3bcd9eb43

16053300035 has 4 divisors (see below), whose sum is σ = 19263960048. Its totient is φ = 12842640024.

The previous prime is 16053300019. The next prime is 16053300047. The reversal of 16053300035 is 53000335061.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53000335061 = 192789491319.

It is a cyclic number.

It is not a de Polignac number, because 16053300035 - 24 = 16053300019 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16053299977 and 16053300013.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1605329999 + ... + 1605330008.

It is an arithmetic number, because the mean of its divisors is an integer number (4815990012).

Almost surely, 216053300035 is an apocalyptic number.

16053300035 is a deficient number, since it is larger than the sum of its proper divisors (3210660013).

16053300035 is an equidigital number, since it uses as much as digits as its factorization.

16053300035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3210660012.

The product of its (nonzero) digits is 4050, while the sum is 26.

Adding to 16053300035 its reverse (53000335061), we get a palindrome (69053635096).

The spelling of 16053300035 in words is "sixteen billion, fifty-three million, three hundred thousand, thirty-five".

Divisors: 1 5 3210660007 16053300035