Base | Representation |
---|---|
bin | 1110100110100011011010… |
… | …0100011010101001011011 |
3 | 2002211220001121221222102121 |
4 | 3221220312210122221123 |
5 | 4101023132314042233 |
6 | 54051444003442111 |
7 | 3244654224014602 |
oct | 351506644325133 |
9 | 62756047858377 |
10 | 16055503268443 |
11 | 5130112035561 |
12 | 19737b7686337 |
13 | 8c60484445a2 |
14 | 3d713a4b6a39 |
15 | 1cc99198892d |
hex | e9a3691aa5b |
16055503268443 has 4 divisors (see below), whose sum is σ = 16107801325000. Its totient is φ = 16003205211888.
The previous prime is 16055503268429. The next prime is 16055503268459. The reversal of 16055503268443 is 34486230555061.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16055503268443 - 25 = 16055503268411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16055503268243) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26149027818 + ... + 26149028431.
It is an arithmetic number, because the mean of its divisors is an integer number (4026950331250).
Almost surely, 216055503268443 is an apocalyptic number.
16055503268443 is a deficient number, since it is larger than the sum of its proper divisors (52298056557).
16055503268443 is an equidigital number, since it uses as much as digits as its factorization.
16055503268443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52298056556.
The product of its (nonzero) digits is 10368000, while the sum is 52.
The spelling of 16055503268443 in words is "sixteen trillion, fifty-five billion, five hundred three million, two hundred sixty-eight thousand, four hundred forty-three".
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