1611317137 has 4 divisors (see below), whose sum is σ = 1706100516. Its totient is φ = 1516533760.

The previous prime is 1611317131. The next prime is 1611317153. The reversal of 1611317137 is 7317131161.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 473671696 + 1137645441 = 21764^2 + 33729^2 .

It is a cyclic number.

It is not a de Polignac number, because 1611317137 - 2¹⁵ = 1611284369 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1611317099 and 1611317108.

It is not an unprimeable number, because it can be changed into a prime (1611317131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47391664 + ... + 47391697.

It is an arithmetic number, because the mean of its divisors is an integer number (426525129).

Almost surely, 2^1611317137 is an apocalyptic number.

1611317137 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

It is an amenable number.

1611317137 is a deficient number, since it is larger than the sum of its proper divisors (94783379).

1611317137 is an equidigital number, since it uses as much as digits as its factorization.

1611317137 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94783378.

The product of its digits is 2646, while the sum is 31.

The square root of 1611317137 is about 40141.2149417528. The cubic root of 1611317137 is about 1172.3582447362.

Adding to 1611317137 its reverse (7317131161), we get a palindrome (8928448298).

The spelling of 1611317137 in words is "one billion, six hundred eleven million, three hundred seventeen thousand, one hundred thirty-seven".