161135423546737 has 4 divisors (see below), whose sum is σ = 161135701954560. Its totient is φ = 161135145138916.

The previous prime is 161135423546729. The next prime is 161135423546749. The reversal of 161135423546737 is 737645324531161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 161135423546737 - 2³ = 161135423546729 is a prime.

It is a super-4 number, since 4×161135423546737⁴ (a number of 58 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (161135423576737) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138333937 + ... + 139493902.

It is an arithmetic number, because the mean of its divisors is an integer number (40283925488640).

Almost surely, 2^{161135423546737} is an apocalyptic number.

It is an amenable number.

161135423546737 is a deficient number, since it is larger than the sum of its proper divisors (278407823).

161135423546737 is an equidigital number, since it uses as much as digits as its factorization.

161135423546737 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278407822.

The product of its digits is 38102400, while the sum is 58.

The spelling of 161135423546737 in words is "one hundred sixty-one trillion, one hundred thirty-five billion, four hundred twenty-three million, five hundred forty-six thousand, seven hundred thirty-seven".