Base | Representation |
---|---|
bin | 1110101010000001101001… |
… | …1110000011100101110001 |
3 | 2010001121001022020010002120 |
4 | 3222200122132003211301 |
5 | 4103012322303144413 |
6 | 54135111500104453 |
7 | 3252165502424565 |
oct | 352403236034561 |
9 | 63047038203076 |
10 | 16115161381233 |
11 | 5153446529702 |
12 | 1983286b35129 |
13 | 8cb8650c9145 |
14 | 3d9d997b16a5 |
15 | 1ce2d41a6723 |
hex | ea81a783971 |
16115161381233 has 4 divisors (see below), whose sum is σ = 21486881841648. Its totient is φ = 10743440920820.
The previous prime is 16115161381217. The next prime is 16115161381283. The reversal of 16115161381233 is 33218316151161.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 16115161381233 - 24 = 16115161381217 is a prime.
It is not an unprimeable number, because it can be changed into a prime (16115161381283) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2685860230203 + ... + 2685860230208.
It is an arithmetic number, because the mean of its divisors is an integer number (5371720460412).
Almost surely, 216115161381233 is an apocalyptic number.
It is an amenable number.
16115161381233 is a deficient number, since it is larger than the sum of its proper divisors (5371720460415).
16115161381233 is an equidigital number, since it uses as much as digits as its factorization.
16115161381233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5371720460414.
The product of its digits is 77760, while the sum is 42.
The spelling of 16115161381233 in words is "sixteen trillion, one hundred fifteen billion, one hundred sixty-one million, three hundred eighty-one thousand, two hundred thirty-three".
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