16115231002441 has 4 divisors (see below), whose sum is σ = 16115303457792. Its totient is φ = 16115158547092.

The previous prime is 16115231002379. The next prime is 16115231002513. The reversal of 16115231002441 is 14420013251161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16115231002441 - 2¹³ = 16115230994249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16115231002141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35893021 + ... + 36339226.

It is an arithmetic number, because the mean of its divisors is an integer number (4028825864448).

Almost surely, 2^{16115231002441} is an apocalyptic number.

It is an amenable number.

16115231002441 is a deficient number, since it is larger than the sum of its proper divisors (72455351).

16115231002441 is an equidigital number, since it uses as much as digits as its factorization.

16115231002441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72455350.

The product of its (nonzero) digits is 5760, while the sum is 31.

The spelling of 16115231002441 in words is "sixteen trillion, one hundred fifteen billion, two hundred thirty-one million, two thousand, four hundred forty-one".