1611768013057 has 4 divisors (see below), whose sum is σ = 1706577896196. Its totient is φ = 1516958129920.

The previous prime is 1611768013043. The next prime is 1611768013069. The reversal of 1611768013057 is 7503108671161.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 809998200001 + 801769813056 = 899999^2 + 895416^2 .

It is a cyclic number.

It is not a de Polignac number, because 1611768013057 - 2⁷ = 1611768012929 is a prime.

It is a super-2 number, since 2×1611768013057² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1611768012998 and 1611768013016.

It is not an unprimeable number, because it can be changed into a prime (1611768013007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47404941544 + ... + 47404941577.

It is an arithmetic number, because the mean of its divisors is an integer number (426644474049).

Almost surely, 2^{1611768013057} is an apocalyptic number.

1611768013057 is a gapful number since it is divisible by the number (17) formed by its first and last digit.

It is an amenable number.

1611768013057 is a deficient number, since it is larger than the sum of its proper divisors (94809883139).

1611768013057 is an equidigital number, since it uses as much as digits as its factorization.

1611768013057 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94809883138.

The product of its (nonzero) digits is 211680, while the sum is 46.

The spelling of 1611768013057 in words is "one trillion, six hundred eleven billion, seven hundred sixty-eight million, thirteen thousand, fifty-seven".