1613016155713 has 4 divisors (see below), whose sum is σ = 1614018653380. Its totient is φ = 1612013658048.

The previous prime is 1613016155683. The next prime is 1613016155719. The reversal of 1613016155713 is 3175516103161.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 799938838449 + 813077317264 = 894393^2 + 901708^2 .

It is a cyclic number.

It is not a de Polignac number, because 1613016155713 - 2¹³ = 1613016147521 is a prime.

It is a super-2 number, since 2×1613016155713² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1613016155719) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 501246420 + ... + 501249637.

It is an arithmetic number, because the mean of its divisors is an integer number (403504663345).

Almost surely, 2^{1613016155713} is an apocalyptic number.

It is an amenable number.

1613016155713 is a deficient number, since it is larger than the sum of its proper divisors (1002497667).

1613016155713 is a wasteful number, since it uses less digits than its factorization.

1613016155713 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1002497666.

The product of its (nonzero) digits is 56700, while the sum is 40.

The spelling of 1613016155713 in words is "one trillion, six hundred thirteen billion, sixteen million, one hundred fifty-five thousand, seven hundred thirteen".