Base | Representation |
---|---|
bin | 11110000011011111… |
… | …10111001000010011 |
3 | 1112122111200211212001 |
4 | 33001233313020103 |
5 | 231021133414110 |
6 | 11225034414431 |
7 | 1110565033435 |
oct | 170157671023 |
9 | 45574624761 |
10 | 16135451155 |
11 | 69300502aa |
12 | 3163891417 |
13 | 16a1b5cc45 |
14 | ad0d50655 |
15 | 64684e63a |
hex | 3c1bf7213 |
16135451155 has 4 divisors (see below), whose sum is σ = 19362541392. Its totient is φ = 12908360920.
The previous prime is 16135451153. The next prime is 16135451161. The reversal of 16135451155 is 55115453161.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 16135451155 - 21 = 16135451153 is a prime.
It is a super-3 number, since 3×161354511553 (a number of 32 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16135451153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1613545111 + ... + 1613545120.
It is an arithmetic number, because the mean of its divisors is an integer number (4840635348).
Almost surely, 216135451155 is an apocalyptic number.
16135451155 is a deficient number, since it is larger than the sum of its proper divisors (3227090237).
16135451155 is an equidigital number, since it uses as much as digits as its factorization.
16135451155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3227090236.
The product of its digits is 45000, while the sum is 37.
The spelling of 16135451155 in words is "sixteen billion, one hundred thirty-five million, four hundred fifty-one thousand, one hundred fifty-five".
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