Base | Representation |
---|---|
bin | 10111011110101111011… |
… | …001111000000111010001 |
3 | 12201020212110101212101221 |
4 | 113132233121320013101 |
5 | 202414030204012431 |
6 | 3233131314525041 |
7 | 224401260504142 |
oct | 27365731700721 |
9 | 5636773355357 |
10 | 1613555532241 |
11 | 57233a03a4a4 |
12 | 220874596781 |
13 | b9208424333 |
14 | 5814cb45ac9 |
15 | 2be8b6bd111 |
hex | 177af6781d1 |
1613555532241 has 8 divisors (see below), whose sum is σ = 1614569261184. Its totient is φ = 1612542125040.
The previous prime is 1613555532179. The next prime is 1613555532263. The reversal of 1613555532241 is 1422355553161.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1613555532241 - 221 = 1613553435089 is a prime.
It is a super-3 number, since 3×16135555322413 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1613555532271) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10375131 + ... + 10529503.
It is an arithmetic number, because the mean of its divisors is an integer number (201821157648).
Almost surely, 21613555532241 is an apocalyptic number.
It is an amenable number.
1613555532241 is a deficient number, since it is larger than the sum of its proper divisors (1013728943).
1613555532241 is a wasteful number, since it uses less digits than its factorization.
1613555532241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160871.
The product of its digits is 540000, while the sum is 43.
The spelling of 1613555532241 in words is "one trillion, six hundred thirteen billion, five hundred fifty-five million, five hundred thirty-two thousand, two hundred forty-one".
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