Base | Representation |
---|---|
bin | 1110101011110111001001… |
… | …1010000011001100101011 |
3 | 2010011121110101112000022020 |
4 | 3222331302122003030223 |
5 | 4104021421040402011 |
6 | 54201405310155523 |
7 | 3254363213121342 |
oct | 352756232031453 |
9 | 63147411460266 |
10 | 16146701497131 |
11 | 5165861062597 |
12 | 19894097b2ba3 |
13 | 90182058aa0a |
14 | 3db70c5a2b59 |
15 | 1d002d101006 |
hex | eaf7268332b |
16146701497131 has 4 divisors (see below), whose sum is σ = 21528935329512. Its totient is φ = 10764467664752.
The previous prime is 16146701497117. The next prime is 16146701497187. The reversal of 16146701497131 is 13179410764161.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 16146701497131 - 226 = 16146634388267 is a prime.
It is a super-2 number, since 2×161467014971312 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (16146701297131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2691116916186 + ... + 2691116916191.
It is an arithmetic number, because the mean of its divisors is an integer number (5382233832378).
Almost surely, 216146701497131 is an apocalyptic number.
16146701497131 is a deficient number, since it is larger than the sum of its proper divisors (5382233832381).
16146701497131 is an equidigital number, since it uses as much as digits as its factorization.
16146701497131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5382233832380.
The product of its (nonzero) digits is 762048, while the sum is 51.
The spelling of 16146701497131 in words is "sixteen trillion, one hundred forty-six billion, seven hundred one million, four hundred ninety-seven thousand, one hundred thirty-one".
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