Base | Representation |
---|---|
bin | 1001011001100110110… |
… | …1001010000100000001 |
3 | 120102211200201010022001 |
4 | 2112121231022010001 |
5 | 10121214042313242 |
6 | 202104425344001 |
7 | 14444635645504 |
oct | 2263155120401 |
9 | 512750633261 |
10 | 161492541697 |
11 | 625413698a3 |
12 | 2736b638001 |
13 | 122c854a1a6 |
14 | 7b5dc3513b |
15 | 4302a11eb7 |
hex | 2599b4a101 |
161492541697 has 4 divisors (see below), whose sum is σ = 161493482416. Its totient is φ = 161491600980.
The previous prime is 161492541689. The next prime is 161492541703. The reversal of 161492541697 is 796145294161.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 796145294161 = 7 ⋅113735042023.
It is a cyclic number.
It is not a de Polignac number, because 161492541697 - 23 = 161492541689 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (161492541667) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131463 + ... + 583324.
It is an arithmetic number, because the mean of its divisors is an integer number (40373370604).
Almost surely, 2161492541697 is an apocalyptic number.
It is an amenable number.
161492541697 is a deficient number, since it is larger than the sum of its proper divisors (940719).
161492541697 is an equidigital number, since it uses as much as digits as its factorization.
161492541697 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 940718.
The product of its digits is 3265920, while the sum is 55.
The spelling of 161492541697 in words is "one hundred sixty-one billion, four hundred ninety-two million, five hundred forty-one thousand, six hundred ninety-seven".
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