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161492541697 = 225931714787
BaseRepresentation
bin1001011001100110110…
…1001010000100000001
3120102211200201010022001
42112121231022010001
510121214042313242
6202104425344001
714444635645504
oct2263155120401
9512750633261
10161492541697
11625413698a3
122736b638001
13122c854a1a6
147b5dc3513b
154302a11eb7
hex2599b4a101

161492541697 has 4 divisors (see below), whose sum is σ = 161493482416. Its totient is φ = 161491600980.

The previous prime is 161492541689. The next prime is 161492541703. The reversal of 161492541697 is 796145294161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 796145294161 = 7113735042023.

It is a cyclic number.

It is not a de Polignac number, because 161492541697 - 23 = 161492541689 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (161492541667) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131463 + ... + 583324.

It is an arithmetic number, because the mean of its divisors is an integer number (40373370604).

Almost surely, 2161492541697 is an apocalyptic number.

It is an amenable number.

161492541697 is a deficient number, since it is larger than the sum of its proper divisors (940719).

161492541697 is an equidigital number, since it uses as much as digits as its factorization.

161492541697 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 940718.

The product of its digits is 3265920, while the sum is 55.

The spelling of 161492541697 in words is "one hundred sixty-one billion, four hundred ninety-two million, five hundred forty-one thousand, six hundred ninety-seven".

Divisors: 1 225931 714787 161492541697