Base | Representation |
---|---|
bin | 10111100001010000010… |
… | …111110110110010101001 |
3 | 12201111211200001122222220 |
4 | 113201100113312302221 |
5 | 202440043032244223 |
6 | 3234255310104253 |
7 | 224525222315442 |
oct | 27412027666251 |
9 | 5644750048886 |
10 | 1616256134313 |
11 | 5734a54a7837 |
12 | 2212a8aab089 |
13 | b9548a8bb22 |
14 | 583276942c9 |
15 | 2c0988216e3 |
hex | 178505f6ca9 |
1616256134313 has 4 divisors (see below), whose sum is σ = 2155008179088. Its totient is φ = 1077504089540.
The previous prime is 1616256134309. The next prime is 1616256134329. The reversal of 1616256134313 is 3134316526161.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1616256134313 - 22 = 1616256134309 is a prime.
It is a super-2 number, since 2×16162561343132 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1616256134413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 269376022383 + ... + 269376022388.
It is an arithmetic number, because the mean of its divisors is an integer number (538752044772).
Almost surely, 21616256134313 is an apocalyptic number.
It is an amenable number.
1616256134313 is a deficient number, since it is larger than the sum of its proper divisors (538752044775).
1616256134313 is an equidigital number, since it uses as much as digits as its factorization.
1616256134313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 538752044774.
The product of its digits is 233280, while the sum is 42.
The spelling of 1616256134313 in words is "one trillion, six hundred sixteen billion, two hundred fifty-six million, one hundred thirty-four thousand, three hundred thirteen".
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