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161638379113 = 547295499779
BaseRepresentation
bin1001011010001001100…
…1011110111001101001
3120110012212010102121211
42112202121132321221
510122013411112423
6202131115233121
714451356360461
oct2264231367151
9513185112554
10161638379113
1162606718692
12273b04487a1
131231c81c513
147b75358ba1
15431071d10d
hex25a265ee69

161638379113 has 4 divisors (see below), whose sum is σ = 161933879440. Its totient is φ = 161342878788.

The previous prime is 161638379093. The next prime is 161638379137. The reversal of 161638379113 is 311973836161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 161638379113 - 229 = 161101508201 is a prime.

It is a super-2 number, since 2×1616383791132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (161638379173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147749343 + ... + 147750436.

It is an arithmetic number, because the mean of its divisors is an integer number (40483469860).

Almost surely, 2161638379113 is an apocalyptic number.

It is an amenable number.

161638379113 is a deficient number, since it is larger than the sum of its proper divisors (295500327).

161638379113 is an equidigital number, since it uses as much as digits as its factorization.

161638379113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 295500326.

The product of its digits is 489888, while the sum is 49.

The spelling of 161638379113 in words is "one hundred sixty-one billion, six hundred thirty-eight million, three hundred seventy-nine thousand, one hundred thirteen".

Divisors: 1 547 295499779 161638379113