Base | Representation |
---|---|
bin | 10111100100111101011… |
… | …110110001001010000001 |
3 | 12201220002220101121202010 |
4 | 113210331132301022001 |
5 | 203021214420141213 |
6 | 3240154132443133 |
7 | 225025625003430 |
oct | 27447536611201 |
9 | 5656086347663 |
10 | 1620234146433 |
11 | 575156a33161 |
12 | 2220191794a9 |
13 | b9a30c82356 |
14 | 585c3b23117 |
15 | 2c22cba1ac3 |
hex | 1793d7b1281 |
1620234146433 has 8 divisors (see below), whose sum is σ = 2468928223168. Its totient is φ = 925848083664.
The previous prime is 1620234146417. The next prime is 1620234146441. The reversal of 1620234146433 is 3346414320261.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1620234146433 - 24 = 1620234146417 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1620234146391 and 1620234146400.
It is not an unprimeable number, because it can be changed into a prime (1620234146483) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38577003466 + ... + 38577003507.
It is an arithmetic number, because the mean of its divisors is an integer number (308616027896).
Almost surely, 21620234146433 is an apocalyptic number.
It is an amenable number.
1620234146433 is a deficient number, since it is larger than the sum of its proper divisors (848694076735).
1620234146433 is an equidigital number, since it uses as much as digits as its factorization.
1620234146433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 77154006983.
The product of its (nonzero) digits is 248832, while the sum is 39.
Adding to 1620234146433 its reverse (3346414320261), we get a palindrome (4966648466694).
The spelling of 1620234146433 in words is "one trillion, six hundred twenty billion, two hundred thirty-four million, one hundred forty-six thousand, four hundred thirty-three".
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