1625141040313 has 4 divisors (see below), whose sum is σ = 1857304046080. Its totient is φ = 1392978034548.

The previous prime is 1625141040307. The next prime is 1625141040331. The reversal of 1625141040313 is 3130401415261.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1625141040313 - 2¹³ = 1625141032121 is a prime.

It is a super-2 number, since 2×1625141040313² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1625141040353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116081502873 + ... + 116081502886.

It is an arithmetic number, because the mean of its divisors is an integer number (464326011520).

Almost surely, 2^{1625141040313} is an apocalyptic number.

It is an amenable number.

1625141040313 is a deficient number, since it is larger than the sum of its proper divisors (232163005767).

1625141040313 is an equidigital number, since it uses as much as digits as its factorization.

1625141040313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 232163005766.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 1625141040313 its reverse (3130401415261), we get a palindrome (4755542455574).

The spelling of 1625141040313 in words is "one trillion, six hundred twenty-five billion, one hundred forty-one million, forty thousand, three hundred thirteen".