162540113 has 4 divisors (see below), whose sum is σ = 166504548. Its totient is φ = 158575680.

The previous prime is 162540097. The next prime is 162540127. The reversal of 162540113 is 311045261.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 37368769 + 125171344 = 6113^2 + 11188^2 .

It is a cyclic number.

It is not a de Polignac number, because 162540113 - 2⁴ = 162540097 is a prime.

It is a super-3 number, since 3×162540113³ (a number of 26 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (162540143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1982156 + ... + 1982237.

It is an arithmetic number, because the mean of its divisors is an integer number (41626137).

Almost surely, 2^162540113 is an apocalyptic number.

It is an amenable number.

162540113 is a deficient number, since it is larger than the sum of its proper divisors (3964435).

162540113 is an equidigital number, since it uses as much as digits as its factorization.

162540113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3964434.

The product of its (nonzero) digits is 720, while the sum is 23.

The square root of 162540113 is about 12749.1220482039. The cubic root of 162540113 is about 545.7413394187.

Adding to 162540113 its reverse (311045261), we get a palindrome (473585374).

The spelling of 162540113 in words is "one hundred sixty-two million, five hundred forty thousand, one hundred thirteen".