Base | Representation |
---|---|
bin | 11110010010111010… |
… | …00110100000011011 |
3 | 1112222111222222002001 |
4 | 33021131012200123 |
5 | 231302234014011 |
6 | 11245534021431 |
7 | 1114025050336 |
oct | 171135064033 |
9 | 45874888061 |
10 | 16264751131 |
11 | 6997034292 |
12 | 319b047877 |
13 | 16c2891bc5 |
14 | b041ab61d |
15 | 652d907c1 |
hex | 3c974681b |
16264751131 has 4 divisors (see below), whose sum is σ = 16460712072. Its totient is φ = 16068790192.
The previous prime is 16264751077. The next prime is 16264751143. The reversal of 16264751131 is 13115746261.
16264751131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16264751131 is a prime.
It is a super-2 number, since 2×162647511312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16264751731) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97980346 + ... + 97980511.
It is an arithmetic number, because the mean of its divisors is an integer number (4115178018).
Almost surely, 216264751131 is an apocalyptic number.
16264751131 is a deficient number, since it is larger than the sum of its proper divisors (195960941).
16264751131 is an equidigital number, since it uses as much as digits as its factorization.
16264751131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 195960940.
The product of its digits is 30240, while the sum is 37.
The spelling of 16264751131 in words is "sixteen billion, two hundred sixty-four million, seven hundred fifty-one thousand, one hundred thirty-one".
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