Base | Representation |
---|---|
bin | 100101000100111010011111… |
… | …100011011000101101110011 |
3 | 210101100220022110102102111220 |
4 | 211010322133203120231303 |
5 | 132333130422213313210 |
6 | 1334451114001240123 |
7 | 46230041516524635 |
oct | 4504723743305563 |
9 | 711326273372456 |
10 | 163065405213555 |
11 | 47a59717155a59 |
12 | 16357202333043 |
13 | 6ccb003a58710 |
14 | 2c3a59cb16a55 |
15 | 13cba8ab13c70 |
hex | 944e9f8d8b73 |
163065405213555 has 16 divisors (see below), whose sum is σ = 280974236676000. Its totient is φ = 80278353335808.
The previous prime is 163065405213521. The next prime is 163065405213619. The reversal of 163065405213555 is 555312504560361.
It is not a de Polignac number, because 163065405213555 - 218 = 163065404951411 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 163065405213498 and 163065405213507.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 418116423430 + ... + 418116423819.
It is an arithmetic number, because the mean of its divisors is an integer number (17560889792250).
Almost surely, 2163065405213555 is an apocalyptic number.
163065405213555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
163065405213555 is a deficient number, since it is larger than the sum of its proper divisors (117908831462445).
163065405213555 is a wasteful number, since it uses less digits than its factorization.
163065405213555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 836232847270.
The product of its (nonzero) digits is 8100000, while the sum is 51.
The spelling of 163065405213555 in words is "one hundred sixty-three trillion, sixty-five billion, four hundred five million, two hundred thirteen thousand, five hundred fifty-five".
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