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1640113 = 9531721
BaseRepresentation
bin110010000011010110001
310002022210221
412100122301
5404440423
655053041
716640446
oct6203261
93068727
101640113
11a20272
12671181
134556a7
143099cd
15225e5d
hex1906b1

1640113 has 4 divisors (see below), whose sum is σ = 1642788. Its totient is φ = 1637440.

The previous prime is 1640083. The next prime is 1640131. The reversal of 1640113 is 3110461.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3110461 = 8934949.

It can be written as a sum of positive squares in 2 ways, for example, as 954529 + 685584 = 977^2 + 828^2 .

It is a cyclic number.

It is not a de Polignac number, because 1640113 - 213 = 1631921 is a prime.

It is a Duffinian number.

1640113 is a lucky number.

It is not an unprimeable number, because it can be changed into a prime (1640183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 93 + ... + 1813.

It is an arithmetic number, because the mean of its divisors is an integer number (410697).

21640113 is an apocalyptic number.

It is an amenable number.

1640113 is a deficient number, since it is larger than the sum of its proper divisors (2675).

1640113 is an equidigital number, since it uses as much as digits as its factorization.

1640113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2674.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1640113 is about 1280.6689658144. The cubic root of 1640113 is about 117.9300792317.

Adding to 1640113 its reverse (3110461), we get a palindrome (4750574).

The spelling of 1640113 in words is "one million, six hundred forty thousand, one hundred thirteen".

Divisors: 1 953 1721 1640113