1640154132211 has 4 divisors (see below), whose sum is σ = 1874461865392. Its totient is φ = 1405846399032.

The previous prime is 1640154132209. The next prime is 1640154132241. The reversal of 1640154132211 is 1122314510461.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1640154132211 - 2¹ = 1640154132209 is a prime.

It is a super-3 number, since 3×1640154132211³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1640154132241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117153866580 + ... + 117153866593.

It is an arithmetic number, because the mean of its divisors is an integer number (468615466348).

Almost surely, 2^{1640154132211} is an apocalyptic number.

1640154132211 is a deficient number, since it is larger than the sum of its proper divisors (234307733181).

1640154132211 is an equidigital number, since it uses as much as digits as its factorization.

1640154132211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 234307733180.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 1640154132211 its reverse (1122314510461), we get a palindrome (2762468642672).

The spelling of 1640154132211 in words is "one trillion, six hundred forty billion, one hundred fifty-four million, one hundred thirty-two thousand, two hundred eleven".